First Term
Exam 2075 Computer Science Questions Solved
Group A
[Fundamentals - 30 Marks]
1. Answer the following questions: [7x2=14]
a) What is telecommunication? Write 2/2 advantages
and disadvantages of computer
network.
Ans: Telecommunication is a
system of transmission of sounds, images, texts or data in the form of
electronic signals.
Any two advantages of computer network are
as follows:
i) The computers on a network can share hardware devices like printer, hard disk, scanner etc.
ii) Software packages can be shared between network connected computers.
i) The computers on a network can share hardware devices like printer, hard disk, scanner etc.
ii) Software packages can be shared between network connected computers.
Any two
disadvantages of computer network are as follows:
i) The sharing of information
may leak the privacy of other clients.
ii) If any computer system in a network gets affected by computer virus, there is a big chance of spreading computer viruses on other computers on the network.
ii) If any computer system in a network gets affected by computer virus, there is a big chance of spreading computer viruses on other computers on the network.
b) What do you mean by transmission medium? Write its types.
Ans: Transmission medium is a
pathway through which data are transmitted in a network. Its types are:
i) Guided
transmission medium
ii)Unguided
transmission medium
c) Define network protocols with some
examples.
Ans: A
network protocol is a set of rules by which computers on the network
communicate with each other. Some examples of protocols are: TCP/IP, SMTP, POP,
HTTP etc.
d) Define the terms: MODEM and Router.
Ans: MODEM
is a device which is used to transfer the data of one computer to another
computer using telephone lines.
A router
is an intelligent network device which connects multiple networks that uses the
same protocol and forwards data packets from one network to another.
e) What is E-mail? Write its advantages.
Ans: E-mail (Electronic mail)
is one of the most popular services provided by the internet which exchanges
messages between the computers over the internet. Its advantages are:
i) It
allows to send and receive message across the world at very low cost.
ii) Multiple copies of same message can be sent to many people.
ii) Multiple copies of same message can be sent to many people.
f) What is internet? Explain its any two
services.
Ans: Internet is an
interconnection of several thousands of computers of different types belonging
to the various networks all over the world. Any two services of internet are:
IRC: Internet
Relay Chat is one of the important services provided by the internet which
allows the user to communicate with other people in real time.
E-Commerce: It is the buying and selling of goods over the internet.
g) What do you mean by uploading and
downloading?
Ans: Uploading refers to
copying files or documents, programs or data from the user computer to the
internet server.
Downloading refers to the copying files or document
or program or data from the internet server to the user computer.
2. a) Perform the following binary calculations: [3x1=3]
i) (10101 + 11101) - 1011
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1
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0
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1
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0
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1
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+
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1
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1
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1
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0
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1
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1
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1
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0
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0
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1
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0
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-
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1
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0
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1
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1
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1
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0
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0
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1
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1
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1
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\ (10101 + 11101) - 1011 = 100111
ii) (11011 x 111)
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1
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1
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0
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1
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1
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|||
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´
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1
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1
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1
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1
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1
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0
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1
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1
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|||
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1
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1
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0
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1
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1
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´
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1
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1
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0
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1
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1
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´
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´
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1
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0
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1
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1
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1
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1
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0
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1
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(11011 x 111) = 10111101
iii) (1011011) / (101)
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1
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0
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1)
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1
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0
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1
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1
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0
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1
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1(
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1
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0
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0
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1
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0
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1
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0
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1
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||||||||||||
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´
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´
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´
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1
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0
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1
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||||||||
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1
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0
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1
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||||||||||||
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´
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´
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´
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1
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0
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1
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Quotient = 10010
Remainder = 1
b) Perform as indicated: [3x1=3]
i) (364)8 into Decimal
Soln:
= 3´82 + 6´81+4´80
= 3´64 + 6´8 + 4´1
=192 + 48 + 4
=244
(364)8 = (244)10
ii) (945)10 into Hexa
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16
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945
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Remainder
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16
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59
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1
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16
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3
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11
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16
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0
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3
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\(945)10 = (3B1)16
iii) (101101011)2 into Octal
Soln:
Converting Binary to Octal,
101 = 5
101 = 5
011=3
=553
\(101101011)2 = (553)8
3. Match the following:[4x0.5=2]
Group A Group B
a) Node i) powerful computer
b) Protocol ii) prevents gaining access
c) Scan disk iii) checking for disk error
d) Firewall iv) workstation
v) rules for network communication
Answers:
Group A Group B
a) Node i) workstation
b) Protocol ii) rules for network communication
c) Scan disk iii) checking for disk error
d) Firewall iv) prevents gaining access
4. Select the correct answer: [4x0.5=2]
a) Unbounded communication medium is ...................
i) Satetllite ii) Dial Up iii) Fiber Optics iv) UTP
Ans: Satellite
b) The process of converting digital signals into analog signals.
i) Modulation ii) Demodulation iii) Both i) and ii) iv) None of them
Ans: Modulation
c) Device used to connect different type of network protocol.
i) MODEM ii) Gateway iii) Bridge iv) NIC
Ans: Gateway
d) Connection of computer between two different countries.
i) WAN ii) MAN iii) WLAN iv) Wi-MAX
Ans: WAN
5. Give the appropriate technical terms of the following: [6x0.5=3]
a) A hardware device that provide common wiring point in LAN.
Ans: hub
b) Protocol used to receive e-mail from mail server.
Ans: POP
c) The cabling structure of interconnected computers in LAN.
Ans: Topology
d) Protocol used to transfer files on the WWW.
Ans: FTP
e) A program that allows a user to interact with web pages.
Ans: Web browser
f) Doing business through internet.
Ans: E-commerce
6. Write the full form of the following: [6x0.5=3]
a) UTP: Unshielded Twisted Pair
b) MAC : Media Access Control
c) URL: Uniform Resource Locator
d) HTTP: Hyper Text Transfer Protocol
e) ISDN : Integrated Services Digital Network
f) ARPA : Advanced Research Projects Agency
Group A Group B
a) Node i) powerful computer
b) Protocol ii) prevents gaining access
c) Scan disk iii) checking for disk error
d) Firewall iv) workstation
v) rules for network communication
Answers:
Group A Group B
a) Node i) workstation
b) Protocol ii) rules for network communication
c) Scan disk iii) checking for disk error
d) Firewall iv) prevents gaining access
4. Select the correct answer: [4x0.5=2]
a) Unbounded communication medium is ...................
i) Satetllite ii) Dial Up iii) Fiber Optics iv) UTP
Ans: Satellite
b) The process of converting digital signals into analog signals.
i) Modulation ii) Demodulation iii) Both i) and ii) iv) None of them
Ans: Modulation
c) Device used to connect different type of network protocol.
i) MODEM ii) Gateway iii) Bridge iv) NIC
Ans: Gateway
d) Connection of computer between two different countries.
i) WAN ii) MAN iii) WLAN iv) Wi-MAX
Ans: WAN
5. Give the appropriate technical terms of the following: [6x0.5=3]
a) A hardware device that provide common wiring point in LAN.
Ans: hub
b) Protocol used to receive e-mail from mail server.
Ans: POP
c) The cabling structure of interconnected computers in LAN.
Ans: Topology
d) Protocol used to transfer files on the WWW.
Ans: FTP
e) A program that allows a user to interact with web pages.
Ans: Web browser
f) Doing business through internet.
Ans: E-commerce
6. Write the full form of the following: [6x0.5=3]
a) UTP: Unshielded Twisted Pair
b) MAC : Media Access Control
c) URL: Uniform Resource Locator
d) HTTP: Hyper Text Transfer Protocol
e) ISDN : Integrated Services Digital Network
f) ARPA : Advanced Research Projects Agency
Group B
[Programming - 20 Marks]
7a) What is variable? List the Qbasic Operators. [1]
Ans: The data items whose value
changes during the execution of a program is called variable. The list of
QBasic operators are:
i) Arithmetic operators
ii) Relational operators
iii) Logical Operators
iv) String operator
b) Why QBasic is called modular porgramming? [1]
Ans: QBasic is called modular programming because it divides
program into many small, manageable, logical and functional modules or blocks.
c) Write any two advantages of modular programming. [1]
Ans: The advantages of modular programming are:
i) Different programmers can design different program modules independently, which is required in a large and complex program.
ii) It is easy to design code and test the program modules independently.
i) Different programmers can design different program modules independently, which is required in a large and complex program.
ii) It is easy to design code and test the program modules independently.
d) Write the purpose of the following built - in functions. [1]
i) MID$ ( ) : It is a string function
that returns the specified number of characters from the specified location of
string.
ii) INT ( ) : It rounds and returns
the largest integer less than or equal to a numeric expression.
8. Rewrite the given program after correcting the bugs. [2]
REM program to display reverse of supplied string
DECLARE SUB REVERSE (A$)
CLS
INPUT "Enter the value"; A$
CALL REVERSE$ (A$)
END
SUB REVERSE (A$)
FOR J = 1 TO LEN(A$)
B$ = MID$(A$, 1, J)
P$ = P$ + B$
NEXT J
PRINT A$
END SUB
Debugged Program:
REM program to display reverse of supplied string
DECLARE SUB REVERSE (A$)
CLS
INPUT "Enter the value"; A$
CALL REVERSE (A$)
END
SUB REVERSE (A$)
FOR J = LEN(A$) TO 1 STEP -1
B$ = MID$(A$, J, 1)
P$ = P$ + B$
NEXT J
PRINT P$
END SUB
REM program to display reverse of supplied string
DECLARE SUB REVERSE (A$)
CLS
INPUT "Enter the value"; A$
CALL REVERSE$ (A$)
END
SUB REVERSE (A$)
FOR J = 1 TO LEN(A$)
B$ = MID$(A$, 1, J)
P$ = P$ + B$
NEXT J
PRINT A$
END SUB
Debugged Program:
REM program to display reverse of supplied string
DECLARE SUB REVERSE (A$)
CLS
INPUT "Enter the value"; A$
CALL REVERSE (A$)
END
SUB REVERSE (A$)
FOR J = LEN(A$) TO 1 STEP -1
B$ = MID$(A$, J, 1)
P$ = P$ + B$
NEXT J
PRINT P$
END SUB
9. Write the output of the following program. [2]
DECLARE SUB num ( )
CLS
CALL num
END
SUB num
P = 2
A = 1
FOR K = 7 to 1 STEP -2
N = N + A
PRINT N
A = A + P
NEXT K
END SUB
OUTPUT:
1
4
9
16
10. Study the following program and answer the given questions. [3x1=3]
DECLARE SUB check(a$)
a$ = "Information Communication Technology"
CALL check(a$)
END
SUB check(a$)
b = LEN(a$)
count = 2
WHILE count<=b
x$ = x$ + MID$(a$, count, 1)
count = count + 1
WEND
PRINT x$
END SUB
a) List the operators in above program.
Ans: The operator used in the above program are: = , <= and +
b) Write the name of sub procedure in the above program.
Ans: The name of sub procedure is check.
c) What will be the value of 'b' in the above program?
Ans: The value of b is 36.
11. a) Write a program using sub procedure to print series: 3, 33, 333, ...upto 5th terms. - [3]
DECLARE SUB SERIES ()
CLS
CALL SERIES
END
SUB SERIES
A= 3
FOR I = 1 TO 5
PRINT A
A= A* 10 + 3
NEXT I
END SUB
b) Write a program using SUB......END SUB to print only middle number among three supplied numbers. [Hint: Neither greater nor smaller] - [3]
DECLARE SUB MIDDLE(A, B,
C)
CLS
INPUT “ENTER ANY THREE
NUMBERS”; A, B, C
CALL MIDDLE (A, B, C)
END
SUB MIDDLE (A, B, C)
IF A > B AND A < C
OR A < B AND A > C THEN
PRINT A; “IS MIDDLE
NUMBER”
ELSEIF B > A AND B
< C OR B < A AND B > C THEN
PRINT B; “IS MIDDLE
NUMBER”
ELSE
PRINT C; “IS MIDDLE
NUMBER”
END
IF
END SUB
c) Write a program using function procedure to print volume of cylinder.
[Hint: Volume = Pie*R^2] - [3]
END SUB
c) Write a program using function procedure to print volume of cylinder.
[Hint: Volume = Pie*R^2] - [3]
DECLARE FUNCTION VOLUME (R, H)
CLS
INPUT “ENTER RADIUS”; R
INPUT “ENTER HEIGHT”; H
PRINT “VOLUME OF CYLINDER ”; VOLUME(R, H)
END
FUNCTION VOLUME (R, H)
VOLUME = 3.14 * R ^ 2 * H
END FUNCTION
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